SqlGeometry.STWithin-Methode

Determines whether the current SqlGeometry is completely within the specified SqlGeometry instance.

Namespace:  Microsoft.SqlServer.Types
Assembly:  Microsoft.SqlServer.Types (in Microsoft.SqlServer.Types.dll)

Syntax

'Declaration
<SqlMethodAttribute(IsDeterministic := True, IsPrecise := False)> _
Public Function STWithin ( _
    other As SqlGeometry _
) As SqlBoolean
'Usage
Dim instance As SqlGeometry 
Dim other As SqlGeometry 
Dim returnValue As SqlBoolean 

returnValue = instance.STWithin(other)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public SqlBoolean STWithin(
    SqlGeometry other
)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public:
SqlBoolean STWithin(
    SqlGeometry^ other
)

[<SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)>]
member STWithin : 
        other:SqlGeometry -> SqlBoolean

public function STWithin(
    other : SqlGeometry
) : SqlBoolean

Parameter

• other
  Typ: Microsoft.SqlServer.Types.SqlGeometry
  The SqlGeometry instance to compare to the current SqlGeometry.

Rückgabewert

Typ: System.Data.SqlTypes.SqlBoolean
Returns true if a SqlGeometry instance is completely within another SqlGeometry instance; otherwise, returns false.

Hinweise

This method always returns nullein NULL-Verweis (Nothing in Visual Basic) if the spatial reference IDs (SRIDs) of the SqlGeometry instances do not match.

Siehe auch

Verweis

SqlGeometry Klasse

Microsoft.SqlServer.Types-Namespace