Método STWithin
Determines whether the current SqlGeometry is completely within the specified SqlGeometry instance.
Namespace: Microsoft.SqlServer.Types
Assembly: Microsoft.SqlServer.Types (em Microsoft.SqlServer.Types.dll)
Sintaxe
'Declaração
<SqlMethodAttribute(IsDeterministic := True, IsPrecise := False)> _
Public Function STWithin ( _
other As SqlGeometry _
) As SqlBoolean
'Uso
Dim instance As SqlGeometry
Dim other As SqlGeometry
Dim returnValue As SqlBoolean
returnValue = instance.STWithin(other)
[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public SqlBoolean STWithin(
SqlGeometry other
)
[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public:
SqlBoolean STWithin(
SqlGeometry^ other
)
[<SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)>]
member STWithin :
other:SqlGeometry -> SqlBoolean
public function STWithin(
other : SqlGeometry
) : SqlBoolean
Parâmetros
- other
Tipo: Microsoft.SqlServer.Types. . :: . .SqlGeometry
The SqlGeometry instance to compare to the current SqlGeometry.
Valor de retorno
Tipo: System.Data.SqlTypes. . :: . .SqlBoolean
Returns true if a SqlGeometry instance is completely within another SqlGeometry instance; otherwise, returns false.
Comentários
This method always returns null Nothing nullptr unit uma referência nula (Nothing no Visual Basic) if the spatial reference IDs (SRIDs) of the SqlGeometry instances do not match.